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Example Uplink Cell Loading for Data Service

Feb 18,2011 by alperen

image

In this
example, rather than showing the number of users, we show the total
throughput (in Kbps) for a given cell loading.
If we look again at Equation 12-10, we note that the equation can be simplified
if we assume that all users have the same data rate. The equation is
then as follows:
Load factor  N  (1  i)/[1  (C/(a  R(Eb/No)))] (Equation 12-11)
If we note that the term C/(a  R(Eb/No)) is far greater than 1 for most services,
then we can further simply the equation to be
Load factor  N  (1  i)/[C/(a  R(Eb/No))] (Equation 12-12)
To get the total throughput (rate times number of users), we rearrange
to get
Throughput  R  N  [Load factor C]/[(Eb/No)  (1  i)] (Equation 12-13) Example assumptions
a  1.0
Eb/No  1 dB(  1.259)
i  50% (that is, of the total interference at the base station, one third is
being received from other cells).
Thus, for a load factor of 50 percent, we have a total throughput of 1,106
Kbps. For a load factor of 60 percent, we have a total throughput of 1,220
Kbps.
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